I was wondering if anyone has much experience with pioneer amps. I am considering this amp because I believe that it is capable of running my polk audio MMC690 6x9's really well. It doesnt have a lot of fancy high pass crossover in it but i dont think i really need that for 6x9's. They are rated for bass to like around 50 hz i believe but i dont know that for sure i just can't remember the rating. Anyways, this amp has 125 watts a channel on 2 channels so i think that it would run those polks which are rated for 100 watts really good with excess power if needed.
Also why i am considering this amp is because i have recently bought an alpine type R 10" sub and i want to confirm that my old amp (usa2200, 200 wattsX2/600Watts x1) is actually doing those numbers. They are printed on the cover and in the manual but i am begining to wonder if they arent peak values instead of rms? also, there is no actual mention of RMS in the manual anywheres so that why i am becoming more and more suspicious.
Anyways, this pioneer amp definetely has 380 watts bridged at 4ohms so I can at least put this amount to my type r 10" and see what happens. I think it would move it good.
But what is your guys opinion of pioneer amps?
Any hinsight much appreciated.
Dave
Replies (5)
dkh on 06/28/2006 21:00:21
here is a link to that amps specs from pioneer
http://www.pioneerelectronics.com/pna/v3/pg/product/details/0,,2076_310069933_152734431,00.html
swez on 06/28/2006 22:36:12
This amp appears to be geared more for sub applications. The LPF is the give away point.
The manual says there is a switch for full range, (no filtering) or a fixed LPF. (80 Hz., 12dB/octave)
If you really want to know the power your USA 2200F is putting out to the sub, you'll need an AC volt meter. I can walk you through the steps if you wish to know how to get the nitty gritty on that amps output value.
Cheers,
Swez
PS Amp Manual
http://www.pioneerelectronics.com/pio/pe/images/portal/cit_11221/187219818GM-5100TOwnersManual.pdf
dkh on 06/28/2006 23:49:11
Ok to recap the procedure.
1. Put multimeter to VAC range 50 VAC or higher
2. Obtain disc with 40, 50, 80, pink noise
3. Put terminals onto the speaker output from the amp that you want to measure, polarity doesnt matter, this is ac voltage
4. play sound at each frequancy and record the highest voltage
5. use formula v = p^1/2 * r to obtain the power
6. take power and multiply it by the approximate efficiency factor for the type of amp it is. (0.5-0.6 for class a/b, 0.75-0.8 for class d)
7. b****h to self that you listened to the guy at the pawnshop when he said " this amp is good to go bud, how much speaker wire do you need with that?"
dkh on 06/29/2006 00:00:26
p ^ 1/2 is the same as saying "take the square root of p"
also, power (p) is in watts
R i believe is by taking a resistance reading of the speaker
though this changes as you apply current to the speaker so i dont really know what to use for R
how do we obtain R? anyone know?
swez on 06/29/2006 08:36:56
If we know P, (Watts) and we know E, (Voltage) using Ohm's Law, we can determine R. (Resistance in Ohms... static or dynamic)
R = E x E/P or E sq/P
Your list is a good summary of our YIM chat David!
I especially like the insightful comment on #7.
FYI: Consider the source of the information and their motivations as well. Some people have a hidden agenda and it may not be in your best interest to follow them. Sad, but true! COFFEE
Swez
PS For the amp you will be testing, the target range for voltage measurements is more like 35-36 VAC. With a true 4 ohm static load, that equates to ~350 watts RMS.
Also why i am considering this amp is because i have recently bought an alpine type R 10" sub and i want to confirm that my old amp (usa2200, 200 wattsX2/600Watts x1) is actually doing those numbers. They are printed on the cover and in the manual but i am begining to wonder if they arent peak values instead of rms? also, there is no actual mention of RMS in the manual anywheres so that why i am becoming more and more suspicious.
Anyways, this pioneer amp definetely has 380 watts bridged at 4ohms so I can at least put this amount to my type r 10" and see what happens. I think it would move it good.
But what is your guys opinion of pioneer amps?
Any hinsight much appreciated.
Dave
Replies (5)
dkh on 06/28/2006 21:00:21
here is a link to that amps specs from pioneer
http://www.pioneerelectronics.com/pna/v3/pg/product/details/0,,2076_310069933_152734431,00.html
swez on 06/28/2006 22:36:12
This amp appears to be geared more for sub applications. The LPF is the give away point.
The manual says there is a switch for full range, (no filtering) or a fixed LPF. (80 Hz., 12dB/octave)
If you really want to know the power your USA 2200F is putting out to the sub, you'll need an AC volt meter. I can walk you through the steps if you wish to know how to get the nitty gritty on that amps output value.
Cheers,
Swez
PS Amp Manual
http://www.pioneerelectronics.com/pio/pe/images/portal/cit_11221/187219818GM-5100TOwnersManual.pdf
dkh on 06/28/2006 23:49:11
Ok to recap the procedure.
1. Put multimeter to VAC range 50 VAC or higher
2. Obtain disc with 40, 50, 80, pink noise
3. Put terminals onto the speaker output from the amp that you want to measure, polarity doesnt matter, this is ac voltage
4. play sound at each frequancy and record the highest voltage
5. use formula v = p^1/2 * r to obtain the power
6. take power and multiply it by the approximate efficiency factor for the type of amp it is. (0.5-0.6 for class a/b, 0.75-0.8 for class d)
7. b****h to self that you listened to the guy at the pawnshop when he said " this amp is good to go bud, how much speaker wire do you need with that?"
dkh on 06/29/2006 00:00:26
p ^ 1/2 is the same as saying "take the square root of p"
also, power (p) is in watts
R i believe is by taking a resistance reading of the speaker
though this changes as you apply current to the speaker so i dont really know what to use for R
how do we obtain R? anyone know?
swez on 06/29/2006 08:36:56
If we know P, (Watts) and we know E, (Voltage) using Ohm's Law, we can determine R. (Resistance in Ohms... static or dynamic)
R = E x E/P or E sq/P
Your list is a good summary of our YIM chat David!
I especially like the insightful comment on #7.
FYI: Consider the source of the information and their motivations as well. Some people have a hidden agenda and it may not be in your best interest to follow them. Sad, but true! COFFEE
Swez
PS For the amp you will be testing, the target range for voltage measurements is more like 35-36 VAC. With a true 4 ohm static load, that equates to ~350 watts RMS.
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