well, i was thinking.
if all a line out converter needs to send out a signal to amps is the proper frequencies, why can't you simply use a line out conerter directly behind the radio on bose systems instead of having to get special, expensive line out converters??
i guess what i'm wondering is, of course you can't tap after the amplifer on bose systems because of the amplified signals, but if the signal is at the radio (non-amplified), then wouldn't it work??
-UK
Replies (1)
swez on 04/7/2006 08:05:50
That's a great question and I may be able to give you a partial answer. It's a bit more complex then one might think. Especially when using passive components.
An LOC is primarily a step down attenuator and impedence matching circuit. It takes HU level AC voltage of say 6-10 volts AC, (~10-25 watts @ 4 ohm loads) and matches that output to a new load and voltage requirement.
The LOC converts this AC signal level, to a usable voltage range and matches the amplifier input impedence. (typically about 10 Kohms)
That usually means a primary and secondary set of inductive coils (transformers) to adjust voltage and pots or fixed resistors to match an given load impedence.
The transformers are often separated by an air gap too. This allows for low noise performance as the transformers are electrically/mechanically "isolated" and can block engine noise issues too.
I don't mean to talk over anyone's head here, but a well designed LOC can be a pretty complex circuit, depending on the functions it needs to perform. This is why many of the better LOC's are pretty expensive devices. The small package is also a factor as component choices are limited to very small devices.
In short, a good LOC circuit will adjust HU signals for target voltage and proper impedence requirements, to a given amplifier input needs.
Does that help?
Swez
if all a line out converter needs to send out a signal to amps is the proper frequencies, why can't you simply use a line out conerter directly behind the radio on bose systems instead of having to get special, expensive line out converters??
i guess what i'm wondering is, of course you can't tap after the amplifer on bose systems because of the amplified signals, but if the signal is at the radio (non-amplified), then wouldn't it work??
-UK
Replies (1)
swez on 04/7/2006 08:05:50
That's a great question and I may be able to give you a partial answer. It's a bit more complex then one might think. Especially when using passive components.
An LOC is primarily a step down attenuator and impedence matching circuit. It takes HU level AC voltage of say 6-10 volts AC, (~10-25 watts @ 4 ohm loads) and matches that output to a new load and voltage requirement.
The LOC converts this AC signal level, to a usable voltage range and matches the amplifier input impedence. (typically about 10 Kohms)
That usually means a primary and secondary set of inductive coils (transformers) to adjust voltage and pots or fixed resistors to match an given load impedence.
The transformers are often separated by an air gap too. This allows for low noise performance as the transformers are electrically/mechanically "isolated" and can block engine noise issues too.
I don't mean to talk over anyone's head here, but a well designed LOC can be a pretty complex circuit, depending on the functions it needs to perform. This is why many of the better LOC's are pretty expensive devices. The small package is also a factor as component choices are limited to very small devices.
In short, a good LOC circuit will adjust HU signals for target voltage and proper impedence requirements, to a given amplifier input needs.
Does that help?
Swez
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