For starters I would like to say Hello to all :)
Im planning on building a Sealed Box with seperate chambers for each sub and I would like someone to let me know if my calculations are correct.
Im using 2 10" MTX Thunder 5000 subs which call for .75^ft each which would bring the total internal volume to 1.50^ft.
I originally came up with internal dimensions
25" x 8.5" x 12.5" which = 2656.25 / 1728 = 1.537^ft.
I read that as a rule of thumb you should increase the volume by 20% to compensate for the volume displaced by the drivers, braces, etc...
correct me if im wrong but 20% of 2656.25 = 531.25 which would give me a total of 3187.5
3187.5 / 1728 = 1.844
now if I bring the internal dimensions to
25" x 10" x 12.5" I which = 3125 / 1728 = 1.808 which I feel would be close enough.
Can someone please tell me if im even close to being right?
on a side note... if im using 3/4 mdf my external dimensions would =
Front / Back - 26.5" x 14"
Top / Bottom - 26.5" x 10"
Sides / Middle - 10" x 12.5"
Thanks in advance to anyone that can help
Dominic
Replies (9)
Tinker18 on 05/14/2005 20:16:34
yes your calculations are corect. 20% of 1.50^ft =.3 ^ft. to be added. are you taking into account the width of the peice of wood that seperates each chamber?
Bass4mePlz on 05/14/2005 21:48:45
Bass4mePlz on 05/14/2005 21:51:18
I think? actually im not too sure which is why I was hopeing someone could help out alil.
Tinker18 on 05/15/2005 00:33:35
ok. do the internal measurements for each chamber. and calculate the space in each chamber, instead of doing the box as a whole.
Bass4mePlz on 05/15/2005 05:59:26
ok so then I would make each box aprox. 0.859^ft
Internal dimensions should = 12.5" x 12.5" x 9.5" (1438.375 / 1728 = 0.859)
I dont think its necessary but it cant hurt so ill make a double wall in the middle...
Total Exterior Dimensions would =
Front/Back - 28" x 14"
Top/Bottom - 28" x 9.5
Sides/Middle) - 12.5" x 9.5"
im about to fall asleep.... let me know what you think
-Dom
Tinker18 on 05/15/2005 08:44:03
seems right to me. although the double wall in the middle is somewhat overkill, it cant hurt. 3/4' mdf is plenty sturdy enough to handle those subs and will not flex. just make sure you seal each chamber well enough. liquid nail has always worked for me in the past, although its a bit messy.
-KP
swez on 05/15/2005 12:21:52
Yes, you have a good plan of attack here. All subs have a range of good operatability. Larger boxes give more deep bass, but power handling will drop a bit. Smaller boxes give great punch bass and power handling is better too.
Quote: "ok so then I would make each box aprox. 0.859^ft"
Internal dimensions should = 12.5" x 12.5" x 9.5" (1438.375 / 1728 = 0.859)"
====================================================
The divider panel is 12.5" x 9.5" x 0.75" = 89in^3
Sub displacement is 105 in^3/sub (per MTX data) x 2 = 210 in^3
Calcs: 1438.4 - (89 +210) = 1138.4/1728 = 0.66 ft^3/chamber
Results: The internal dimensions first used, net a slightly smaller than targeted internals for your subs. The easiest dimension to change would be depth. Just make sure you adjust the internal divider board calculations as you adjust depth to reach your 0.75 ft^3 target.
Looks like the internal target will be 12.5 x 12.5 x 10.25 = 1601.6in^3
Divider: 96in^3
Subs: 210 in^3
1601.6 - 306 = 1295.6/1728 = 0.749 A perfect fit! CLAP
Swez USFLAG
Bass4mePlz on 05/15/2005 13:18:38
Thanks for the help guys!
-Dom
Tinker18 on 05/16/2005 08:34:44
no problem, stick around, you will learn alot.
Im planning on building a Sealed Box with seperate chambers for each sub and I would like someone to let me know if my calculations are correct.
Im using 2 10" MTX Thunder 5000 subs which call for .75^ft each which would bring the total internal volume to 1.50^ft.
I originally came up with internal dimensions
25" x 8.5" x 12.5" which = 2656.25 / 1728 = 1.537^ft.
I read that as a rule of thumb you should increase the volume by 20% to compensate for the volume displaced by the drivers, braces, etc...
correct me if im wrong but 20% of 2656.25 = 531.25 which would give me a total of 3187.5
3187.5 / 1728 = 1.844
now if I bring the internal dimensions to
25" x 10" x 12.5" I which = 3125 / 1728 = 1.808 which I feel would be close enough.
Can someone please tell me if im even close to being right?
on a side note... if im using 3/4 mdf my external dimensions would =
Front / Back - 26.5" x 14"
Top / Bottom - 26.5" x 10"
Sides / Middle - 10" x 12.5"
Thanks in advance to anyone that can help
Dominic
Replies (9)
Tinker18 on 05/14/2005 20:16:34
yes your calculations are corect. 20% of 1.50^ft =.3 ^ft. to be added. are you taking into account the width of the peice of wood that seperates each chamber?
Bass4mePlz on 05/14/2005 21:48:45
Bass4mePlz on 05/14/2005 21:51:18
I think? actually im not too sure which is why I was hopeing someone could help out alil.
Tinker18 on 05/15/2005 00:33:35
ok. do the internal measurements for each chamber. and calculate the space in each chamber, instead of doing the box as a whole.
Bass4mePlz on 05/15/2005 05:59:26
ok so then I would make each box aprox. 0.859^ft
Internal dimensions should = 12.5" x 12.5" x 9.5" (1438.375 / 1728 = 0.859)
I dont think its necessary but it cant hurt so ill make a double wall in the middle...
Total Exterior Dimensions would =
Front/Back - 28" x 14"
Top/Bottom - 28" x 9.5
Sides/Middle) - 12.5" x 9.5"
im about to fall asleep.... let me know what you think
-Dom
Tinker18 on 05/15/2005 08:44:03
seems right to me. although the double wall in the middle is somewhat overkill, it cant hurt. 3/4' mdf is plenty sturdy enough to handle those subs and will not flex. just make sure you seal each chamber well enough. liquid nail has always worked for me in the past, although its a bit messy.
-KP
swez on 05/15/2005 12:21:52
Yes, you have a good plan of attack here. All subs have a range of good operatability. Larger boxes give more deep bass, but power handling will drop a bit. Smaller boxes give great punch bass and power handling is better too.
Quote: "ok so then I would make each box aprox. 0.859^ft"
Internal dimensions should = 12.5" x 12.5" x 9.5" (1438.375 / 1728 = 0.859)"
====================================================
The divider panel is 12.5" x 9.5" x 0.75" = 89in^3
Sub displacement is 105 in^3/sub (per MTX data) x 2 = 210 in^3
Calcs: 1438.4 - (89 +210) = 1138.4/1728 = 0.66 ft^3/chamber
Results: The internal dimensions first used, net a slightly smaller than targeted internals for your subs. The easiest dimension to change would be depth. Just make sure you adjust the internal divider board calculations as you adjust depth to reach your 0.75 ft^3 target.
Looks like the internal target will be 12.5 x 12.5 x 10.25 = 1601.6in^3
Divider: 96in^3
Subs: 210 in^3
1601.6 - 306 = 1295.6/1728 = 0.749 A perfect fit! CLAP
Swez USFLAG
Bass4mePlz on 05/15/2005 13:18:38
Thanks for the help guys!
-Dom
Tinker18 on 05/16/2005 08:34:44
no problem, stick around, you will learn alot.
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